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q) 105 mL of pure water (4°C) is saturated with NH3 gas, producing a solution of density 0.9 g/mL. If this solution contains 30% NH3 by weightt , calculate its volume. (Ans. 166.67 mL)
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3 Answers
Aditya Bhutra
·2012-03-11 22:56:32
let the volume be V ml
weight of soln = d*V = 0.9V
weight of water = (1-30100)*weight of soln = 0.7*0.9V =0.63V
now volume of water = 105ml
weight of water = 1g/cc * 105ml =105g =0.63V
V=166.67 ml