in an oswald walker experiment,dry air was first blown thru a solution containing solute(M=278) in 150 g of water and then also thru pure water.the loss in mass of water is 0.0827g while mass of water absorbed in sulphuric acid is 3.317g.calculate the amount of slute.
1357Po is proportional to mass of water absorbed by sulfuric acid=3.317g
Po-P is proportional to loss in mass of water=0.0827 g
(Po-P)/Po=Xsolute
now find the mass of the solute
1why
Po is proportional to mass of water absorbed by sulfuric acid=3.317g
Po-P is proportional to loss in mass of water=0.0827 g
1sir,is it a rule that we have to take it as u have mentioned in post in an oswald-walker experiment.
like as u have given-
[Po is proportional to mass of water absorbed by sulfuric acid=3.317g
Po-P is proportional to loss in mass of water=0.0827 g]
is it so we have to take it similar always in an oswald-walker experiment.
39www.textbooksonline.tn.nic.in/Books/11/Chemistry-EM/Vol2/c11.pdf
thats the link man
1357(Po-P)/P0=XB
(Po-P)/P=nB/nA=WBMA/WAMB
WB=[(Po-P)/P]*WAMB/MA
W=[0.0827/(3.317-0.0827)]*150*278/18=59.24 gm
