pH

Calculate pH of a 0.016M aqueous solution of Ca(CH₃COO)₂ .K_a=2*10^-5

2 Answers

1357

Manish Shankar ·2008-11-01 06:21:32

Ca(CH₃COO)₂ will break as Ca²⁺ + 2CH₃COO^-

so hydrolysis can be written as

CH₃COO^-+H₂O [eq] OH^-+CH₃COOH

pH=-(1/2)[logK_w+logK_a-logc]

here c is the concentration of CH₃COO^-=2*Ca(CH₃COO)₂=0.032

thanx sir.........

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