1these are the values of individual solubility u can calculate the value of solubility product with help of these
solubility of AgCl in pure water is 8*10-6
solubility of AgBr in pure water is 4*10-6
solubility of AgI in pure water is10-6
find solubility of AgCl when all of these three mixed together???
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15 Answers
62these numbers are not the solubitlity product values na?
otherwise it will be a googly ;)
in either case this is a very good and important question :)
1
1oh is it individual solubilities?
then my ans wont match...
1 min...
i will post agn
1solubility products of-
AgCl: 64E-12 =K1
AgBr: 16E-12 =k2
AgI: E-12 = k3
let solubilities of agcl, agbr and agi be s1, s2, s3 respectively /
due to common ion effect...
Ag+ concentration will be because of all three..
so, we can say,
(s1+s2+s3)s1 = k1. --- 1
(s1+s2+s3)s2 = k2 ----2
(s1+s2+s3)s3 = k3 -----3
from these three eqns,
represent s2, s3 in trms of s1 ...
bus :) [1]
33:(
I was taking s1+s2+s3=another variable y so 3 var and 4 eqns :D
Didn' saw y=s1+s2+s3
:D
