1 g of a moist sample of KCl And KClO3 was dissolved in water and made up to 250 ml. .25 ml of the solution was treated with SO2 to reduce the chlorate to chloride and excess SO2 was removed by boiling . The total chloride was precopatated as Silver Chloride . Wt of the precipatate was .1435 gm. In another experment 25 ml of the original solution was heated with 30 ml of .2 N ferrous sulphate and unreacted ferrous sulphate required 37.5 ml of 0.08 N of an oxidizing agent for complete oxidation . Calculate the ratio of chlorate to chloride in the given mixture.
Ans .5 X 10-3 .
I've tried this for over 2 hrs . PLs Help [194]
1aditya i dont think the ratio could be so less...
case 1:
miliequivalents of AgCl=.1435143.5*1000=1
as Cl+5-------->Cl--6e.....
Mm of KClO3-=6x...if x=Mm of clo3-
CAse 2:
iron sulphate left after rxn=6-3=3
after this i dont know how to proceed......
BUT DEFINITELY THE RATIO IS NOT 5*10^-3
11Avinav ur right .. I am also getting the same thing.... lets see if anyone else solves the ques ...
29Aditya ..i tried using the first hint..i was getting the ratio around 1:1 ...