11Ans 1) BeSO4 > MgSO4 > CaSO4 > SrSO4
Ans 2) Cr > Mn > V > Ti ??????????
Q1 Solublity order
Beso4,MgSO4,CaSO4,SrSO4
Q2 2nd ionisation enthalpy
Cr,V,T,Mn
Q3 
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10 Answers
11
11.BeSO4>MgSO4>CaSO4>SrSO4
agree with tushar.
larger anions SO42-,CO32- compared to cation means that the cationic radius doesnt influence the lattice energy much but the hydration energy decreases down the group,making them lesser soluble.
on the contrary when the anion is of similar size as that of the cation,the radius of teh cation will affect the lattice energy and the decrease in lattice energy will be much more than the decrease in hydration energy which causes the solubility to increase down the group as for hydroxides.
1Ti V Cr Mn
Ti=1s2 2s2 2p6 3s2 3p6 4s2 3d2
V=1s2 2s2 2p6 3s2 3p6 4s2 3d3
Cr=1s2 2s2 2p6 3s2 3p6 4s1 3d5
Mn=1s2 2s2 2p6 3s2 3p6 4s2 3d5
shouldnt it be Ti<V<Cr<Mn
whats the answer?
24@tush ,arka..i too got same answers as urs..but ans given were
1) BeSO4< MgSO4< CaSO4 <SrSO4
2)Cr > Mn >Ti>V
surely they are wrong..
anyone for 3 ?
29@Eureka ..r u sure abt the third equation?
i think there is some problem that shud be M3O4 ..if that's not a redox reaction...or if it's a redox reaction so M is getting reduced then something shud get oxidised also...
Ans 2.. the trend given by Tushar is correct..actually this is given in NCERT..but dont worry such questions wont be asked...as there is no regular trends in d-block....
1eureka,they have 2 b wrong.
CaSO4 is an insoluble white ppt whereas MgSO4 is soluble salt!
24@arka,rickde....ya ans are surely wrong...just wanted to confirm form the genius guys out here [1]
@govind.. the eqn maybe wrong....but lets work through equivalents only ..and not by moles..that way it would be easier
29M + X2 → MX2
3MX2 + X2 → M3X8
M3X8 + 4N2CO3 → M3O4 + 8NX + 4CO2
for one mole of NX ..1/8 mole of M3X8
for 1/8 mole of M3X8 we need 3/8 mole of MX2
for 3/8 mole of MX2 we need 3/8 mole of M
so for 2mol of NX we need 3/4 mole of N..and tht's 42 gram