106all
(a)(b)(c)(d)
Multiple Correct Answer type .
The standard enthalpy change of formation of Al2O3(s) is −1669 kJ mol−1 and the standard enthalpy change of formation of Fe2O3(s) is −822 kJ mol−1.
(a) ∆Hο for the following reaction. Fe2O3(s) + 2Al(s) → 2Fe(s) + Al2O3(s) is -847kJ
(b) the reaction in (a) is exothermic
(c) the magnitude of the entropy change for this reaction will be minimal
(d) No significant change in positional or phase disorder
-
UP 0 DOWN 0 0 7
7 Answers
19initially , i was thinking about all,,,but i refrained because i found out the sign of ΔH0 to be the other way round....may be i have done some calculation errors !
106delta H rkn = delta H products - delta H reactants
= -1669 - (-822) = -847 kJ
as delta H<0 so reaction is exothermic
Entropy change is minimal bcz all species involved are solids.. so no appreciable change in disorder... further moles of reactants=moles of products
there is no phase disorder bcz all the species are solids.