TPQN 28

VITEEE Preparation › Physical Chemistry questions › TPQN 28

In the given reaction at 300K
C₆H₆ + 15/2O₂---------->6CO₂ + 3H₂O enthalpy= -3271kJ
What is change in the internal for the combustion of 1.5 mole of benzene at 300K?
a)-3267.25kJ
b)-4900.88kJ
c)-4906.5kJ
d)-3274.75kJ

#Chemistry #Physical Chemistry

UP 0 DOWN 0 0 5
Post on FacebookPost anonymously?

5 Answers

Rohan Ghosh ·2008-12-14 07:04:25

i think the enthalpy is given per mol
then the answer just
-1.5*(3271)=-4906.5

UP 0 DOWN 0
Post on FacebookPost anonymously?

Aakash Sharawat ·2008-12-14 16:35:36

bingo! i too got the answer same as your answer!
well i am sorry to say that according to the answer key the answer is b!!!!!!!!!

UP 0 DOWN 0
Post on FacebookPost anonymously?

1357

Manish Shankar ·2008-12-14 20:50:18

I think you have to consider Î”nRT part

Î”H=Î”U+Î”nRT

UP 0 DOWN 0
Post on FacebookPost anonymously?

Aakash Sharawat ·2008-12-17 16:22:35

@manish: bhaiya by using this we are getting -3659KJ which none of the options above! i think that they must have given the wrong answer!

UP 0 DOWN 0
Post on FacebookPost anonymously?

skygirl ·2008-12-17 21:01:56

the ans should be 'c'.
no explanation given in the answer key in support of b ??

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

TPQN 28

5 Answers

Your Answer

Add Image

Similar Questions