1sir normal means is it not to be taken as 1 normal?
volumetric analysis 1.6 g of pyrolusite was treated with 60 ml of normal oxalic acid and some sulphuric acid .the oxalic acid left undecomposed was made upto 250ml ,25 ml of this solution required 32ml of 0.1Npottasium permanganate.calculate the percentage of pure mno2 in pyrolusite
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1357volumetric analysis 1.6 g of pyrolusite was treated with 60 ml of ??? normal oxalic acid a
How much normal?
1357miiliequivalent of KMnO4=32*0.1=3.2
milliequivalent of unused oxalic acid=3.2*(250/25)=32
miliequivalent of oxalic acid taken =60*1=60
miliequivalent of oxalic acid reacted with pyrolusite=60-32=28
millimol of MnO2=28/2=14
wt of MnO2=14*(55+32)/1000=1.218
%=1.218/1.6=76.125 %
