volumetric analysis

JEE Mains 2015 Online › Physical Chemistry questions › volumetric analysis

volumetric analysis 1.6 g of pyrolusite was treated with 60 ml of normal oxalic acid and some sulphuric acid .the oxalic acid left undecomposed was made upto 250ml ,25 ml of this solution required 32ml of 0.1Npottasium permanganate.calculate the percentage of pure mno2 in pyrolusite

#Chemistry #Physical Chemistry

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5 Answers

1357

Manish Shankar ·2009-04-05 04:22:02

volumetric analysis 1.6 g of pyrolusite was treated with 60 ml of ??? normal oxalic acid a

How much normal?

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rahul ·2009-04-05 04:23:59

sir normal means is it not to be taken as 1 normal?

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1357

Manish Shankar ·2009-04-05 04:27:02

hmm yes it has to be 1

I thought she missed something

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1357

Manish Shankar ·2009-04-05 04:35:08

miiliequivalent of KMnO₄=32*0.1=3.2

milliequivalent of unused oxalic acid=3.2*(250/25)=32

miliequivalent of oxalic acid taken =60*1=60

miliequivalent of oxalic acid reacted with pyrolusite=60-32=28

millimol of MnO₂=28/2=14

wt of MnO₂=14*(55+32)/1000=1.218

%=1.218/1.6=76.125 %

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sanjana chintalacheruvu ·2009-04-05 04:45:24

thank u so much

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