71
Vivek @ Born this Way
·2011-04-26 21:25:43
My attempt:
I got the idea that for the time to uniform, the amount of water falling through the orifice should be constant with time. But since pressure is varying with the time and also the slope is changing (and also Cross Section) we need to derive the equation of a curve suitable to this. But how do i approach this mathematically is unknown to me.
1
samagra Kr
·2011-04-27 00:49:41
is it like y=kx4 ???
you can take water filled upto height y,where radius is x.
apply A.v= constant
and bernoulli's principle.
21
Shubhodip
·2011-04-28 06:58:47
yes,i also think y= kx^4
@Vivek '' I got the idea that for the time to uniform, the amount of water falling through the orifice should be constant with time.''
This is not correct. Take O as origin(figure).The velocity of water along y direction should be constant.ie dy/dt = k. The key equation is
dy* (pi)x2 = [√(2gy)]dt*A (where A is the small area of orifice O)
so dy/dt = [√(2gy)]*A(pi)x2 = k
which gives y = c x4
71
Vivek @ Born this Way
·2011-05-01 23:49:55
It is something or order y = cx4 .
71
Vivek @ Born this Way
·2011-05-01 23:51:27
Subhodip.. Now that it's correct. Please latexify your solution and elaborate more so that anyone who sees this post could understand.