106http://olympiads.hbcse.tifr.res.in/announcements/INO%202010%20Papers
11 Answers
24From where did u get them ??
i mean i wanted the q paper.....if u can tell the source
106
1Is the answer key, or solution to the paper is available?
I have the paper and have tried some. Wanted to check the answers.
106yeah.. they are .. look at the link abv
only answers available ..
11Needless to mention the pressure will be he same in all the 3 compartments, and temperature will be same in the last 2 compartments.
With these things in mind, we have the common pressure of the 3 compartments as P_2 and the temp in the last 2 compartments as \frac{9T_0}{4} and the temp in A1 as T1.
With (A2+A3) as an adiabatic system, we have the equations...
2V_2+V_1=3V_0 ............(1), where V2 is the volumne of each compartment A2 & A3. V1 is the volumne of A1.
Also P_2V_2=\frac{9}{4}P_0V_0.......(2)
P_2V_1=\frac{T_1}{T_0}P_0V_0.........(3).
Adiabatic relationships in combined (A2+A3) gives 2P_0(2V_0)^{\frac{5}{3}}=2P_2(2V_2)^{\frac{5}{3}}
Substitute P2 from (2) to get
\boxed{V_2=\frac{8}{27}V_0}.
We also get \boxed{P_2=\frac{243}{32}P_0}.
From (1) & (3), we can get \boxed{V_1=\frac{65}{27}V_0} & \boxed{T_1=\frac{585}{32}T_0}.
b) Ext. work done is \frac{4(P_0V_0-\frac{9}{4}P_0V_0)}{\gamma -1} while the internal energy gives ΔU as CvΔT.
Adding which we have W.D. as \boxed{W=\frac{15P_0V_0}{4}}.
c)total heat given is CpΔT, use R.To=P0V0.
Finally d) is settled by the fact that entropy change of (A2+A3) is 0, while for A1 it is simply Heat givenchange in temp..
P.S - I cud not find the answers in that link u've given.
Pls confirm the ans, and give me the link to the same.
66@Soumik
Those answers are correct. The entropy change for A1 is
\dfrac{3R}{2}\ln\dfrac{585}{32}+R\ln\dfrac{65}{27}
106thanks...
the link for the answers is
http://olympiads.hbcse.tifr.res.in/announcements/ino-2010-solutions
(they changed the structure. .earlier it was in the same page)