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Integral Of (a) Sec(X)+1 (B) ∫{cos(5x) + cos(4x)}/1-2cos(3X) (C) ∫ {F(x)φ'(x) + F'(x)φ(x)} / (F(x)φ(x)+1) φ(x)f(x) + 1 ...
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∫x2/√1-x4dx ...
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∫ dx/cosx + cosec x ∫ 3cot3x - cotx/tanx - 3tan3x ∫tan{x -k}tan{x+k}tan2x ...
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√((1-√x)/(1+√x)) ...
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\hspace{-16}\bf{(1)\;\; \int\frac{1}{(1+x^4)^{\frac{1}{4}}}dx}$\\\\\\ $\bf{(2)\;\; \int\frac{1}{(1-x^4)^{\frac{1}{4}}}dx}$\\\\\\ $\bf{(3)\;\;\int\frac{1}{(1+x^4)}dx}$\\\\\\ $\bf{(4)\;\;\int\frac{1}{(1+x^6)}dx}$ ...
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∫√(sin x-sin3x/1-sin 3x)dx ...
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∫(x3m+x2m+xm)(2x2m+3xm+6)1/mdx .For any natural no. m, x>0. ...
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∫sec2x/(secx+tanx)9/2 ...
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Int. x^2 dx/(x^2 + bx +12) ...
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1 ∫cosx-sinx/ sin2x 2∫sinx/(1-sinx)0.5 ...
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∫√cotx+√tanx ...
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(A) ∫dx/ sin11xcosx (B) ∫ cos3x/sin11x please show the steps ...
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\hspace{-16}\bf{(1)\;\; \int\sqrt{a+\sqrt{b+\sqrt{x}}}\; dx}$\\\\\\ $\bf{(2)\;\;\int \sqrt{1+2\sqrt{x-x^2}}\;dx}$ ...
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∫sin(4x)etan2x ...
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∫sin(4x)etan2x ...
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(A) ∫1/ cos6(x) + sin6(x) (B) ...
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(a) )\int 1/COS^{6}(x)) + SIN^{6}(X)) ...
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If ∫f(x)sinxcosxdx=lnf(x)/(b2 -a2) +c then f(x)=? ...
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∫ x2/x4+x2-2 dx ...
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√(tanx+2)dx ...
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∫x6 / 1+x5 dx ∫x / 1+x5 dx ...
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∫dx/sin2x+tan2x ...
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Tell me somebody how to integrate this How to integrate dv/ v2+ 2v,??? ...