39same old trick :P
lets see if anyone can guess !!!
There is a square of side 1.
remove a square from the vertex
keep repeating till you get a pattern like in the image....
now if you move from one vertex of the square to the opposite one, then the length traversed is always 2...
But in the limiting case.. when you tend to infinity, the length traversed is √2
Hence 2= √2
What is the flaw?
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6 Answers
62Wow someone has dug out an old thread..
This is interesting... It in one way explains the relevance of limits ;) :P
