many of you have done this
There are 25 horses and 5 race course. that means you can run atmost 5 horses in one race.
What will be the number (minimum) of races required to find the top 3 horses (top means which runs fast)
Those who already know this leave it for sometime :)
1sir i think the answer is 12
first we shld have 5 races & eliminate 10 horses by selecting top 3 frm each
now we have 15 left
so we can have 3 races to select top 3 of each & eliminate 6 horses
races till now 8
now we have 9 more to go
we can have now 2 races 1 ith 5 & one with 4 horses
select 3 frm each
10 till now
have a race between 5 horses & let the 3 winners race with the other resting one
so total no 12
arshad g luks r8 to me
39answer has already been given in #18 dude..
always read complete thread before asking
39First you run each group of 5 in a race, for 5 races total. Then, in the 6th race, you race the champions, to get positions(ranks) for all 5 of those.
they can be x1 x2 x3 x4 x5
y1 y2 y3 y4 y5
z1............................
t1............................
u1..............................
Now, we know the fastest among all is is x1.
The three fastest horses, in order, could be x1,x2,x3 or x1,x2,y1 or x1,y1,y2 or x1,y1,z1.
Race x2,x3,y1,y2, and z1 to determine the 2nd and 3rd fastest horses
16 race have to be conducted.
5 to get the top 5, and then a match betwee the top 5. To get the top 3..........
6well yes a strange horse indeed
thats why not gettin tired perhaps( 2 legs only)
lol:D
71If this horse gets in the race, then Only 1 One match and we have TOP 1. :P
1I will Load a Gun and Shoot in air which three horses will escape first they will be the winner.
No race is required. Prob Solved. ha ha
1hmmm...
i think i got it after making the five groups of all the top 3 horses in each group we can make them race in pairs like all the third ones in 1 group all the 2nd ones in 2nd group and all the first ones in another group. The winers of each group compete to find the final positions
1sir, why did u pick top 3 from each group. the 4th horse in one group may be faster than third of another.didn't get it,sir
1357there is some fault here
how do you know that the second in each group are not as fast as first in other group
1is the question such that all horses have to compete against each other then the answer is wrong
1is the answer 5,sir.
race them in 5 groups. note their timings, get the top 3
1357Hint:
First race them in 5 groups and pick top 3 from all the groups. So now you know the top 3 from all groups
what next?
1is the answer 6
5 races with 5 horses .select the toppers from the 5 races and race them again to decide top 3
1357but 4th will always be behind the 3 horses. So we can easily eliminate 4th one
1sir ,what i'm saying is the 4th on of a particular group may be faster than chosen ones of another group.it is not going to be behind them
1yes bro jagaran is right....if u r saying dat the second of a particular group can be faster than 1st of another group...then the 4th of a particular group can also be faster than the 1st or 2nd of another group....
