03-09-09

Passage

When g(x) and h(x) will be solved by someone..I will post the remaining questions of this passage

Sorry Nishant sir ,if u think this question doesnt deserve to be QOD

12 Answers

24
eureka123 ·

is it easy ?????

try it alll

24
eureka123 ·

no one trying ??

1
injun joe ·

Let f1= ax+b and f2= cx+d
As f1 and f2 are onto,

-a+b=0
a+b=k
-c+d=k
c+d=0

Solving, we get f1 and f2 as
y=k/2(x) + k/2 = f1 and
y=-k/2(x) + k/2 = f2

From graph

1
injun joe ·

the point of intersection is (0,5k)

24
eureka123 ·

what is c and d u have taken ??

also k has to be eliminated ..

so ur ans is not rite..

1
injun joe ·

c and d are arbitrary constants..
And about k, .... :(

24
eureka123 ·

and hint:
dont assume f1x) and f2(x) separately..instead generate them from a single equation f(x) using the conditions

24
eureka123 ·

OK..seems like some one is tryign the ques...

so i will drop a hint

Let f(x)=ax+b
Now use the condition of onto mapping from [-1,1] to [0,k]
and find values of a and b in terms of k

3
msp ·

can we assume f1(x) and f2(x) as y=x and y=-x respectively.

24
eureka123 ·

No

24
eureka123 ·

Looks like everyone has given up on this

1
Arshad ~Died~ ·

ya dude......tried to some extent........but couldnt get it

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