Let f1= ax+b and f2= cx+d
As f1 and f2 are onto,
-a+b=0
a+b=k
-c+d=k
c+d=0
Solving, we get f1 and f2 as
y=k/2(x) + k/2 = f1 and
y=-k/2(x) + k/2 = f2
From graph
Passage
When g(x) and h(x) will be solved by someone..I will post the remaining questions of this passage
Sorry Nishant sir ,if u think this question doesnt deserve to be QOD
Let f1= ax+b and f2= cx+d
As f1 and f2 are onto,
-a+b=0
a+b=k
-c+d=k
c+d=0
Solving, we get f1 and f2 as
y=k/2(x) + k/2 = f1 and
y=-k/2(x) + k/2 = f2
From graph
what is c and d u have taken ??
also k has to be eliminated ..
so ur ans is not rite..
and hint:
dont assume f1x) and f2(x) separately..instead generate them from a single equation f(x) using the conditions
OK..seems like some one is tryign the ques...
so i will drop a hint
Let f(x)=ax+b
Now use the condition of onto mapping from [-1,1] to [0,k]
and find values of a and b in terms of k