1did it using........
sin3x=(3sinx-sin3x) /4
Find the sum of the infinite series...
sin^3x+\frac{sin^33x}{3}+\frac{sin^33^2x}{3^2}+\frac{sin^33^3x}{3^3}+...
(Hint recall the questions I have given during the last few days...)
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9 Answers
62Did I say that this is an infinite series?
btw what you have done is correct.. :)
You killed this one.. (I had thought that this would not be solved this simply.. May be I have repeated the idea a bit too often now ;)
62@Qwerty.. am I not.. even if it is, It is purely unintentional.. (sorry if that is happening.. but with so many requests for answers i miss a lot of them)
23kk....jus jokin ....but i had posted u a few questions in ur scrapbuk earlier ....but they are cleared now .......but yeah ..i wil be coming wid de new ones!!
3if xyz's ans is correct for n terms then the rest is simple we have to apply the limits that n tends to infinity
so S∞=3/4sinx
62Yup it is correct.. i was just pointing out that he missed out that small thing .. [1]
62Dont worry you have enough time to improve.. and you are getting close to doing that :)