what was the warning about [7]
What is
00
Warning: Either dont get confused after seeing the solution or dont see the solution at all....... This might be really dangerous for your limits concept!
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38 Answers
let me get a few posts back... as i saw dis one juzz now...
1/0 is undefined and not indeterminate form... as ∞ is not a defined value, but not an indeterminate value...
0/0 is indeterminate form... the other indeterminate forms are 00, ∞∞, ∞/∞, 0∞, ∞0 and 1∞
after much thinking all i can come up with is
ltx→0x0=1
but 00 is undefined
i dont think i am wrong [1]
i KNOW that I am wrong [4]
@philip
ltx→0x0=1 its indeterminate... not =1
but 0exact/0exact = undefined..
well it is
1) undefined
2) Indeterminate too...
The thing to not is that there are people who have argued that it is actually 1. There is a sense of consensus among a lot of mathematicians that it is 1.
Why calculators show it as 1? Because they have been programmed using limits of sequences! (Almost always!)
And when you take limit xx x going to 0 ... what will be the answer?
Infact it depends on the calculators as to how they have been programmed to find such limits!!! (basically all calculators do approximations!!!!)
i know we can prove x0=1 by writing x0=x/x
but is it perfectly correct !!
maybe im dreaming
gnite ...........
gnite = google nite haha[4] jus kidding
good night
i thought that this might be confusing for people....
but then u guys are smart ;)
no its not that we were not confused but when you say something like that it can scare us
u know just like 12-1-09 QOTD
so i thot there was something worse than this[1]
if 0 is divide d by any no. gives us like 0/1=0....
if any no. is divided by 0 ,ans is ∞ like 1/0=∞..
so 0° can be written as o/o...and from above we can see 2 results are possible...so this value is undefined....
0/0 form in known as indeterminate form...
The error in the proof below is this 0/0 form...
Let a = b
=> ab = b2
=> ab - a2 = b2 - a2
=> a(b-a) = (b+a)(b-a)
=> a = b + a
puttin a = 1, => b = 1 [from the first step]
=> 1 = 1 + 1
=> 1 = 2 .... How?..............
when ur telling a = b i.e, a-b=0
how can you cancel (a-b) from both sides... which can b done nly be done by assuming (a-b)≠0.
either a-b=0 or a=b+a...
both can not occur simultaneously..
strangely my program and the calculator say 1
and this is one of the few times im reluctant to agree
i think 1∞ should be 1 straight away
but it is ltx→1x∞ that causes problems
I think x0 =x/x [7]
so 00 = 0exact/0exact so it is not indeterminate but undefined...
[1]
@philip there is a reason for google to do that
@Pirate: Is ∞ defined for reals??? How something that contains it be?
is it indeterminate or undefined?