1sir plz give mass of trolly & bob
a bob suspended ina trolley is displaced 45* and is released. what is the tension in the strind just after the bob is released?? what is the acceleration of the trolley just after the bob is released??
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9 Answers
1nothing else is given
eg mass of trolley bob etc .. are thy same
i cudnt get the whole picture ..
9rite know dont have paper pen to solve
will post ans tomorrow
HINT
wrt to trolley ,acc of bob must be perpendicular to string
1celestine the scenario is not clear at all to me!
perhaps you can make it ..
1i think we have to assume variables over here.
like m and M
rest is clear isn't it ?
1on the basis of what i have understood it comes pretty straightforward ..
ans=
√2Mm/(2M+m)
M = trolley and m= bob
1oops i missed a g
T=√2Mmg/(2M+m)
now everything else can be calculated
9yes rohans right
u can find a = √2 (M+m)g/(2M + m)
jee 2010 aspirants this is a must do