21th_November_2008

Assume that the day began 10-12 hrs late.. i forgot to post the question today! here it is in a hurrry.. i modified a question of irodov.. Dont have a final solution .. but the fearless and the conceptful should give it a shot :)


A cyllinder(radius R) is made to rotate at ω angular velocity and put at the edge as shown.. the base shows the ground.
The coefficient of friction is k
How many turns will the cylinder make before stopping..?
Assume that k is not large enuf for the sphere to start moving upwards!
*edits: no there is no translation..
friction is on both surfaces.
rotation is anticlockwise

I modified question 1.248 from irodov.

12 Answers

1
Rohan Ghosh ·

is friction there at both the surfaces
and is friction coefficient k such that

the body gives translational motion as well

62
Lokesh Verma ·

no there is no translation..

friction is on both surfaces.

1
Rohan Ghosh ·

answer is coming out to be =

w2mR/8kπA

where A = mg(k+sinθ-kcosθ)/(k2sinθ+sinθ)

now it could be correct

w = intial ang. speed

1
E=mc^2 darkangel ·

my denominator of A is coming (k^2+1)sinθ

62
Lokesh Verma ·

isnt it the same :D

1
E=mc^2 darkangel ·

bit too late

well done rohan

1
ith_power ·

yup. i got the same answer as rohan

62
Lokesh Verma ·

yes rohan and cool spirit.. and Ith Power :)

good work

only thing is that u could cancel out both the m's in the numerator and denominator :)

24
eureka123 ·

This one will be a record....soln posted exactly after 1yr... [3]

1
Arshad ~Died~ ·

gr8 solution....no wonder it took one year.....
:)

62
Lokesh Verma ·

Good work eureka [1]
Aside: there are not as good users as rohan was in physics..

24
eureka123 ·

very true...[1]

and i too found this ques unsolved by luck..then seeing it pending ..decided to post its soln

just wonder why it took so long for anyone to find it unsolved ?

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