How is x2=x+x+x+...........n times?
Isn't it x+x+x+x...............x times [7]
Pls correct me if I'm wrong
x2=x+x+x+.... x times....
take derivative of both side...
2x=1+1+1+... x times
thus, 2x=x!
What is the error?
Does it mean that if f(x)=g(x) then f'(x) ≠g'(x) ??
x^2 as defined above is valid only for whole numbers and is therefore not a continuous function.
Only continuous functions have derivatives.
How is x2=x+x+x+...........n times?
Isn't it x+x+x+x...............x times [7]
Pls correct me if I'm wrong
Then e=mc2 is correct. [3]
(1/2)2 can't be equal to (1/2).(1/2)(1/2).(1/2).........1/2 times [4]
but Aragorn
(1/2)2 is equal to (1/2).(1/2)(1/2).(1/2).........1/2 times
i think it is because the number of terms also vary with x..
nothing to do with cont or discrete.. i think
also because...
1=1/x+1/x+1/x+1/x+....+1/x x times
differentiating both sides
0=-1/x2+(-1/x2)+(-1/x2)+....+(-1/x2) x times
0=-1/x
[3] this is not a solution but another example to what Nishant Bhaiya gave...[3]
another problem in reply to a problem
Whats the reason[7]
I proved by giving a contour example.. but thats the reason [3]
you cant differentiate.. because this function is defined only at points...
it is not a continuous function.....
it is a discrete one..
so there is no question of taking derivatives ;)