1at 01:05 AM,
not confident.
plz reply
The minute and hour hands of the clock meet at 12 o'clock
What is the next time they meet?
*I wud like to believe that this is a physics problem and not a mathematics one ;)
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14 Answers
11ωmin= 2π rad hr-1
ωhr= 2π rad (12hrs)-1
= π/6 rad hr-1
I don't know how to proceed after this. Sorry [2]
1357@Aragorn..you have found the angular velocity
Now try to find the angular position
1@akhil see at 1:05 AM the hour clock would have moved some distance away so not exactly 1.05
i'll solve and tell the ans
112/11 of an hour i.e 720/11 mins
64.something
i.e b4 1.05 am infact im wrong above at 1.05 the hr hand would be behind the min hand sorry for silly reply
****edit****
DONT READ THIS POST
FORGET IF YOU HAVE ALREADY DONE THAT
1a big Sorry to Akhil for confusing him so much
Akhil dont read my posts the ans is 65.45 MINS and my first post was spot on
thanx a milion to manish bhaiyya for pointing that out
i'll edit the prev. post now
33ωmin= 2π rad hr-1
ωhr= 2π rad (12hrs)-1
= π/6 rad hr-1
so for they to meet..
ωmint=ωhrt+2rπ .........t is in hr..
so
2πt = π/6t +2 r π
solving this we get t=12r/11 hrs after 12:00
at 12/11 hrs for r=1
at 24/11 hrs for r=2....
so on...
[3] Plz convert them to hr:min:sec:...
62abhishek ur method is very good..
just one simpler observation would have solved it too...!!
See that in 12 hours, the minute and hour hand would have met exactly 11 times....
hence 12/11 :D
If you want a more "mathematical" method.. then priyam's solution is perfect