1I think capacitance is
C=4Πε0ab/b-a
Derive the capacitance of concentric shells with radius a and b by taking charges Q and -Q on both the surfaces.
Then electric field is found.. and then the work done is found...
-
UP 0 DOWN 0 0 9
9 Answers
39if a charge q is given to the inner spherical conductor, it spreads over the outer surface of it and a charge -q appears on the inner surface of the shell. The electric field is produced onnly between the two.
the potential difference between the two is given by
v=q/4Πε (1/a -1/b)
using c=q/v we get
c=q/4Πε(ab/b-a)
11) we take a gaussian surface in between the two spheres.
we get , E = kQ/r2
2) dV =-E.dr
we find potential by integrting between a to b.
V= kQ(1/a-1/b)
3) then C=Q/V.
is this wat you wanted..... ??
if so, then [1] [this wasnt like QOD]
or else [3]
1yeh hcv mein solved hai n spherical capacitors out of syllb hai :P