6th_November_2008

There are N points in a Plane.

All the points are joined with each other. Note that the line segments are made. The lines are not extended on either sides.

They meet at a lot of points.

What is the number of points where these lines meet.

It is known that no 3 points are on the same line!
edit: Nor do any three lines meet at a single point!

Comment: Tough Looking problem with a 1 line solution!

11 Answers

62
Lokesh Verma ·

Rider: Dont count the points themselves!

Example:

For this figure, the answer is 5

The red colors are the points of intersection
The outside pentagon is the original set of 5 points.

1
Rajat Khanduja ·

Not counting the given points ::


The number of points is equal to the ways of choosing 4 points out of the given N points.
This is so because for every 4 points u can draw 2 diagonals with giving u one intersection point.

Answer is NC 4

Edited by : Nishant Sah to make some part invisible to others.. so that they can try without seeing the solution [1]

62
Lokesh Verma ·

from now on try to use Hide button to try and hide the answer
when u post answers to this kind of question... so that the other people may no be able to see it unless they select the black area!

I am editing your post to make it look like that...

Hidden Message

Btw ur answer is absolutely correct Rajat :)

Good work

1
skygirl ·

62
Lokesh Verma ·

no dear.. this cant be done.. the whole point of the question is that we join only the first n point...

when we do that we get the asterix(star shape) in between...

That is all. We donot want to join any of the points again!

33
Abhishek Priyam ·

Is it given that no three lines meet at same point?

62
Lokesh Verma ·

yes

33
Abhishek Priyam ·

then i think it will be nc4 no of ways of selecting quad out of n points

62
Lokesh Verma ·

yes u r absolutely correct :)

62
Lokesh Verma ·

answer is "somethng <=nC4"

Why i gave this problem is two fold.
1) To highlight this solution
2) To stump those who already knew the solution :P

Actually the problem with this solution as some of u have posted is that there may not be a point inside!

Why? bcos the points are not given to be sides of a convex polygon!!!

I will give an example to drive home my point....

Here, there are 4 points.. the three of the triange and the other 4th point in between. Do these 4 points when joined meet at any point?

NO

So u guys have made a mistake.

But atleast the way u thought was correct!

So u inspite of being a bit ahead of the curve.. failed!

The answer is that we know only an upper limit to this .. that is nC4

33
Abhishek Priyam ·

opse i got trapped....

Actually this problem was in FIITJEE package and with convex. I solved that there, so in a flash (also due to that conves fig) i got that answer although i checked that no two intersections coincides but finally......................................

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