The longer side of the mirror appears perpendicular to both hp and vp
did nt get it..how's dat possible..
ignoring this...
i am getting
theta = (pi)2 - sin-1 34
is it correct???
A mirror 30 X 40 mm is inclined to the wall such that its front view is square of 30 mm side. The longer side of the mirror appears perpendicular to both hp and vp. find the inclination of the mirror with wall.
I am sorry guys i know this website is not the right place to post it but i really needed help..
The longer side of the mirror appears perpendicular to both hp and vp
did nt get it..how's dat possible..
ignoring this...
i am getting
theta = (pi)2 - sin-1 34
is it correct???