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A mirror 30 X 40 mm is inclined to the wall such that its front view is square of 30 mm side. The longer side of the mirror appears perpendicular to both hp and vp. find the inclination of the mirror with wall.

I am sorry guys i know this website is not the right place to post it but i really needed help..

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3 Answers

D Queen ·2011-01-06 07:54:03

hi..

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SANDIPAN CHAKRABORTY ·2011-01-06 12:08:45

The longer side of the mirror appears perpendicular to both hp and vp

did nt get it..how's dat possible..

ignoring this...

i am getting
theta = (pi)2 - sin^-1 34

is it correct???

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D Queen ·2011-01-07 09:43:02

nopes..nishant bhaiya..plz help..!!

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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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