1good Anirudh..U got it right :)...but s = (1/2)at^2 not (1/2)gt^2
In the above figure , if both blocks are at rest at t= 0, find the time after which the blocks collide.Treat the blocks as point masses and the initial separation as √2 m.
Answer - (2/√5)s.
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UP 0 DOWN 0 0 3
3 Answers
11μ1 >1 => 1st block won't move at all!
thus, required time is time for 2nd block to slide down by √2 m.
anet= g/√2 - g/2√2
=g/2√2
=5/√2
Use s= (1/2) gt2 and find t :)
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