check post made abt Q.49
Discuss everything related to 2nd Phase test here [1]
All queries ... related to any question/explanation or anything [3]
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94 Answers
well sky.. that is an interesting problem
It will be like go front come back.. then go front..
it is like upto 10 he will go like this
6-4+6-4+6-4+6-4+6-4
now he will move +6 to move to 16 meters.!
I hope this is now obvious?
see,real gas obeys equation at low pressure & high temperature, ie over a SPECIFIC RANGE ONLY....................
Its given there isotopes have non-integral masses which is not true
vishal
2 wrongs dont make it a right... please see what u are doing in both the cases. If u are not convinced.. pls read it yet agian..
q 55
i have asssumed ma ans correct ie
%N2O4=25%
and then proved myself correct by finding net mass of N2O4 & NO2 in mix & added them to get 57.5 ie 2wice the given vapour density
arey baba , check peter atkins. no ? mein page nos bhi diya hoon .If I'm wrong in understanidgn then just explain in the fourm.
thanks.
Arrey yaar.. the quesiton is NOT about IDEAL GAS
IT IS ABOUT REAL GAS!! READ FIRST!
one mo dude. Q.49 the thing i've got is the tension in the string with the pulleys. so the tension in the one attahced to the balance has twice the tension ,thus it should tilt ot right no?
But Where comes the question of IDEAL GAS
Nothing is mentioned in the question regarding IDEAL GAS
no it is not applicable over wide range. it obeys near boyles temperature so over a specific range must be the ans
i agree with srinath & dimensions
no way The ideal gas eqn is appplicable ear to boyle temp . for a considerable amt of pressure , but not any temp . no?
i dont knwo what u are trying to say vishal... sorry if i am repeating what u are saying
so its mass in mixture=.25*92==.5.M ...........1
also NO2=.75*46=.75M ..........2
% by mass = .5/(.5+.75) = .40
q55 net mass=57.5
if N2O4=25%
so its mass in mixture=.25*92=23...........1
also NO2=.75*46=34.5..........2
1& 2 add to 57.5
about 72...
I think u guys are talking about Ideal gas equation being true in a small range (Low Pressure, High Temperature!) or is it something else that I am not able to understand? I dont see how it is not applicable over a large range!
i forgot..
Q 8
Statement 1: Derivative of k.f(x) = k. Derivative of f(x)
Statement 2: Derivative of f(x).g(x) = f(x).g'(x)+f'(x).g(x). Derivative of a constant is zero!
I was saying about k=0 and f(x)=[x]
at integral RHS of statement 1 is not defined but LHS is defined so hows it equal..
equality means 100% identical in every aspects naa ??
can anyone send me pdf file of 2nd phase test please my id is apurva.1991@gmail.com
thanks
Yeah Celestine .....I have cancelled the question
The answer is coming 37 hours which is not in the option