BT QUESTIONS ( PREVIOUS YEARS)

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2 moles of an ideal diatomic gas are in the cylinder at temperature T. Suppose on supplying heat to the gas its temperature remains constant but' n ' moles get dissociated into atoms. IF heat supplied to the gas is 0.25 RT, then value of n is

A) 1 mole B) 0.5 mole C) 0.25 moles D) 1.2 mole

#Physics #Thermal physics

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rahul nair ·2010-02-28 05:53:14

0.25?

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rahul nair ·2010-02-28 06:03:10

no change in internal energy, as temp is constant.....
so, Heat supplied=Work done

0.25RT=PdV=\DeltanRT

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Manmay kumar Mohanty ·2010-02-28 06:05:18

yaar ans. given is 1 mole,

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Anirudh Kumar ·2010-02-28 17:38:42

i think internal energy would have been same if moles had also been the same.

my soln:

since voume is same thus W=0

=> Î”Q= Î”U
0.25RT = {(2-n)*2.5RT+ 2n*1.5RT}- {2*2.5RT} = 0.25*nRT

=>n=1

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BT QUESTIONS ( PREVIOUS YEARS)

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