Calorimetry

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A ball is dropped on a floor from a height of 2.0m. After the collision it rises upto a height of 1.5m. Assume that 40% of the mechanical energy lost goes as thermal energy into the ball.
Calculate the rise in the temperature of the ball.
Heat Capacity of the ball is 800JK^-1

#Physics #Thermal physics #Calorimetry

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865

Soumyadeep Basu ·2014-02-07 20:41:44

0.005 K.

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Aditya Agarwal No.
Upvote·0· Reply ·2014-02-07 21:37:48
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2305

Shaswata Roy ·2014-02-08 01:12:12

Î”Î¸ = 2.5x10^-3

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Aditya Agarwal yeah. but how? how did you eliminate m? since heat capacity of the ball is given?
Upvote·0· Reply ·2014-02-08 01:24:44
Shaswata Roy If this is the right answer then I'm pretty sure there is some mistake in the question.I assumed that by heat capacity you meant specific heat capacity.
Upvote·0· Reply ·2014-02-08 02:02:43
Aditya Agarwal Ok. (y)
Upvote·0· Reply ·2014-02-08 02:14:21
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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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Calorimetry

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