conduction1

2 Answers

1
satan92 ·

we have

T1 for the right T2 for the left

msdT1/(dt) = 4kA(170-T1)/3L

msdT2/dt=4kA(170-T2)/L

diving both we get

3dT1/(170-T1)=dT2/(170-T2)

integrating we get

(170-T/160)=4/5

thus 170-T=128

T=42

1
gsns gannavarapu ·

can u explain d integrations part a bit mor clearly??

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