we have
T1 for the right T2 for the left
msdT1/(dt) = 4kA(170-T1)/3L
msdT2/dt=4kA(170-T2)/L
diving both we get
3dT1/(170-T1)=dT2/(170-T2)
integrating we get
(170-T/160)=4/5
thus 170-T=128
T=42
we have
T1 for the right T2 for the left
msdT1/(dt) = 4kA(170-T1)/3L
msdT2/dt=4kA(170-T2)/L
diving both we get
3dT1/(170-T1)=dT2/(170-T2)
integrating we get
(170-T/160)=4/5
thus 170-T=128
T=42