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I didnt understand ur ques..On PV graph..there is no straight line passing through oriigin of any process,,
we have isochoric on PT and isobaric on VT
A.
P-V diagram of a monoatomic gas is a straight line passing through origin. The molar heat capacity of the gas in the process will be
1. 3R/2
2. R/2
3. 2R
4. 3R
B.
For a gas , molar specific heat in a process is greater than Cc, which relation is possible PαVβ
, Where α and β are
1. 2 , 1/3
2. 1, 2
3. 1,3
4. 2,3
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8 Answers
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1Hi Eureka....in question it is given that PV graph is a straight line passing through origin....
Hence it is a problem with assumption....don't relate it with theory....
Now to the question...
SInce there is straight line on PV curve hence relation in PV will be..
P = m.V
Now we know that PV = nRT
so m.V^2 = n.RT------(1)
...
also work done or energy = ∫p.dv = ∫m.V.dV= mV^2/2
I.e now energy = 1/2*m.V^2 = nRT/2 {from 1}
Now Molar specific heat = energy /n.T
Molar specific heat = nRT/2.n.T = R/2
Hence second option is correct.
Now for second question.....please clearify what is Cc?
1n this question p=mv thereofre pv^-1=m a constant c=cv+r/1-x
and here x=-1 therote the anser should be 3/2r
3abt the molar heat cap for first question
frm process we get ..... P=kV ....
nCdT =nCvdT + PdV ...FIRST LAW OF TD[dont rem. number [3] it think first only hehe]
rearrangin
C = Cv + P/n dV/dT
also
PV=nRT ,,
or kV^2 = nRT
or dV/dT = nR/2kV ,,,,
or nR/2P
C = Cv + R/2 ..
find Cv for monoatomic .. and find C......
and varun mem. formulas like the 1 u stated is harmful for health!!!!![3]
3question B
assumin by Cc u mean Cv !!!!! [3]
we only need dV/dT >0 [refer prev post!!!]
P^aV^b= c ..
or kV/V^(b/a) = nRT
k V(1-b/a) = nRT ..
clearly ... if 1-b/a > 0 dV/dT>0
or b>a
so option 2,3,4 are right ....
1to convert a real gas to a ideal gas the conditions favorable are
a:high temperature low pressure