HEAT

Hi Eureka....in question it is given that PV graph is a straight line passing through origin....
Hence it is a problem with assumption....don't relate it with theory....

Now to the question...
SInce there is straight line on PV curve hence relation in PV will be..

P = m.V
Now we know that PV = nRT
so m.V^2 = n.RT------(1)
...
also work done or energy = ∫p.dv = ∫m.V.dV= mV^2/2
I.e now energy = 1/2*m.V^2 = nRT/2 {from 1}
Now Molar specific heat = energy /n.T
Molar specific heat = nRT/2.n.T = R/2
Hence second option is correct.

Now for second question.....please clearify what is Cc?

n this question p=mv thereofre pv^-1=m a constant c=cv+r/1-x
and here x=-1 therote the anser should be 3/2r

molar specific heat capacity =1/nΔQ/ΔT
and not workdone/dT

question B

assumin by Cc u mean Cv !!!!! [3]

we only need dV/dT >0 [refer prev post!!!]

P^aV^b= c ..

or kV/V^(b/a) = nRT

k V(1-b/a) = nRT ..

clearly ... if 1-b/a > 0 dV/dT>0

or b>a

so option 2,3,4 are right ....

to convert a real gas to a ideal gas the conditions favorable are
a:high temperature low pressure

wat are u tellin pa ????