3.73 x 10-3 J/s ?
- Aditya Agarwal No.
233 J/sUpvote·0· Reply ·2014-02-11 06:34:11
3.73 x 10-3 J/s ?
Hint: Can you find out the resistance of the tube? Its a kind of structure in which you have to take different elementary cylinders connected in series. Then find out dQ/dt at steady state.