IIT JEE past question Thermodynamics 11

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A gas mixture consists of 2 moles of oxygen and 4 moles of argon at temperature T. Neglecting all vibrational modes, the total internal energy of the system is?

#Physics #Thermal physics

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tapanmast Vora ·2009-03-28 07:41:22

Cv =( n1Cv1 + n2Cv2 )/(n1 + n2)

Cv = 11/6 R

U = nCvT

U = 11RT

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ANKIT MAHATO ·2009-03-28 07:42:18

2*(f_O₂/2) * RT + 4*(f_Ar/2) * RT

2*5/2 RT + 4*3/2*RT = 11RT

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iitimcomin ·2009-03-28 07:42:22

AGREE WIT TAPAN

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ANKIT MAHATO ·2009-03-28 08:25:15

iitcomin .. i have also calculated the the energy based on the very fundamental formula .. . E = n * (degrees of freedom/2) * R T
for n moles of gas ...

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iitimcomin ·2009-03-28 08:27:44

YEP AGREE WIT U TOO........................DIDNT SEE UR POST WEN I POSTED MINE...[1]

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ANKIT MAHATO ·2009-03-28 08:29:12

oh .. yes dude our posts were exactly at 8: 12 p.m .. :)

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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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IIT JEE past question Thermodynamics 11

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