1i guess ideal gas equation shud suffice
Consider a container which contains just one molecule of a gas.
What will happen if you:
(1) double the volume keeping temperature constant
(2) double the temperature keeping pressure constant?
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11 Answers
1PV = nRT
here, n=1/Avo.const. ≈ 0
=> PV = 0
so i dun think it wud matter if we double the vol...
1PV=nRT
wen ?T is constnt
P1V1=P2V2
n s o o n 4 d othr
wen pressure is constnt
V1/T1=V2/T2
train ;)
62pressure is found by the avg no of collisions with the surface... multiplied by the momentum of the particles...
No of collisions will be directly prop to the velocity and the momentum will be directly prop to the velocity again...
Hence it is directly prop to the kinetic energy...
Same with volume... What will happen to the pressure.. (It dpends on the lenght of the container.. )!!
So does the above hint work?
3okie so if we double the volume .. and keep same temp......
the velocity of particle is same but in a given period of time the no. of collisions decreases ... as vol. of container is increased ..... thus pressure reduces .........
if we double temp. velocity √2bles[3]{edited part} ..... thus to keep same pressure the volume has to be increased ... in order to keep ave. no of collisions per second / pressure same ....
62there is one small mistake..
if we double temperature, kinetic energy doubles na? or does velocity doubles?
3vel. √2 times prev. 1 ........ sorry ....... just wanting to say it increases ... only qualitative analysis na...
62yup good work
This is one of the best (Most fundamental) questions of thermoD that I have seen
Godo that you cracked it. I was surprised why not many were attempting this one :)
3didnt see it bhiyya ...... thanks for showin it to me ...........and do check eurekas latest questions soln. please bhiyya..............see if approach is correct...
