Plot a curve b/w P vs V
plot:
A(V0,P0)
B(V0,3P0)
C(3V0,P0)
join A, B, C with straight lines
Find Efficiency
33U must be wondering why q is without pic and pic is put later...
Bcause at that time pic uploder was not ready....... many of U had seen pic uploder frm the 1st day... u joined the site
62yeah.. :D
This is indeed a great problem.
Try solving it.. Definitely a QOD material!
1for A-B PROCESS:
(isochoric) :- NO WORK
ΔQ=ΔU +0 => ΔQ = ΔU = nCvΔT ----1.
Δ(PV)=nRΔT => nΔT= (PΔV+VΔP)/R = (0+ 2P0V0)/R
So, ΔQ = Cv2P0V0/R ----2
for B-C PROCESS:
(kuchh bhi process!!!) :-
ΔQ=0
ΔW= 4P0V0 (area under curve B-C)
for C-A PROCESS:
(isobaric) :-
ΔW = -2P0V0
ΔQP = nCPΔT = -VE QUANTITY (temp decreases).. so not required..
so, efficiency = (total work done)/ (positive heat supplied) X 100
ξ = [2P0V0/R ] / [2P0V0CV/R]
= R/CV x100 = 2/5 % = 40%
1I AM GETTING ANSWER AS 80%!
I WILL GIVE REASON IF IT IS RIGHT !
PLZ TELL ME??
33So much many answers ****edited as told by her :P
But i don't think all is right :P
1:P :P :P :P
grammar mistake :P
'much' answers ??? ... :P
sry! kidding :P
33
plz check it.. it can be wrong :P made it long ago ...
Sorry D is mid point of BC
62well yes it is wrong abhishek.. we saw this last proof..
basically the mistake as i felt was that D is taken as the midpoint! Which is not true (If i remember correctly!!)
Pls check the point D..
33Well what i found then was heat is being absorbed and released about D (where temp is max i suppose)...
But i'm confused now after so "many" (Sky now its alright) answers...
:(
