Thermodynamics-11

BITSAT 2015 Tutorials › Thermal physics questions › Thermodynamics-11

#Physics #Thermal physics

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1057

Ketan Chandak ·2013-04-04 04:37:23

graph will be a parabola...
max temp=255.25K

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Akash Anand Check it again ....answer is different
Upvote·0· Reply ·2013-04-04 05:25:05
Hardik Sheth i am also getting the same ans..[p(initial)+p(final)/2][v(initial)+v(final)/2]=nrt(max)..wer am i wrong..
Upvote·0· Reply ·2013-04-05 02:27:25
Akash Anand Answer is given as 319.4 K well i will check it again.
Upvote·0· Reply ·2013-04-05 03:24:37
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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω