thermodynamics

1] caculate the least amount of work that must be done to freeze one gram of water at 0 degrees by a refrigerator. temperature of surroundings is 27 degrees. how much heat is passed to surroundings in this process? latent heat of fusion = 80 k cal/gram

10 Answers

21
tapanmast Vora ·

Ans : 8000/9Kcal?

1
kamalendu ghosh ·

I am confusedhow r u getting that tapan??

1
skygirl ·

1 clarification reqd : 1 gm of water is initiallly in wat temperature ?

21
tapanmast Vora ·

mathie wats da Ans Dude?

39
Dr.House ·

its my doubt, not for u guys to practice. so u tell me the answer.

39
Dr.House ·

i dont have answer!

21
tapanmast Vora ·

OH NO!!! [2]

wat I did was

w/Q = (T2-T1)/T2

80Kcal/Q = (300-273)/300

sum1 chk my working!!

**edit** OH K [1]

11
virang1 Jhaveri ·

yes it is rite

1
kamalendu ghosh ·

superb!!!

1
skygirl ·

great tapan :)

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