400000

A vertical pole consists of two portions,the lower being 1/3rd of the whole.If the upper portion subtends an angle arctan(1/2) at a point in a horizontal plane through the foot of the plane and distance 40ft from it,then the height of the pole is ________

This sum is easy,but i couldn't understand its geometry !!!!!!!!

7 Answers

1
Pavithra Ramamoorthy ·

NO TENSION............

11
Anirudh Narayanan ·

SEE WHETHER D SKETCH IS RIT......

62
Lokesh Verma ·

Good work aragon :)

11
Anirudh Narayanan ·

Thanx Nishant bhaiyyah. How 2 proceed after this?

P.S:
Aragorn please :)

11
Anirudh Narayanan ·

x/40 = tan[θ+arctan(1/2)]

x/120= tanθ

Will you get answer if you solve these equations?

11
Anirudh Narayanan ·

Answer anyone?

62
Lokesh Verma ·

x/40 = tan[θ+arctan(1/2)]

x/40 = ( tan θ + 1/2 )/ (1-1/2 tan θ)

x/120= tanθ

Substitute tan θ above!

x/40 = (x/120 + 1/2) / (1-1/2.x/120)

this is a quadratic in x... just solve it :)

Your Answer

Close [X]