aur ek trigonometry IMPORATANT

WELL THIS MIGHT SEEM ILLOGOCAL TO FEW PEOPLE BUT I KNOW THAT MOST OF THEM DONNO THIS. BUT VERY USEFUL IN SOME PROBLEMS.

in a triangle ABC, medianof BC , AD is drawn. what is lengthof AD? { in terms of a,b,c ,} D is mid point of BC.

this is easy than previous wala.

8 Answers

COME ON GUYS THIS OUGHT TO BE MUCH MORE EASIER

AD^2= \frac{2a^2+2b^2-c^2}{4}

sry ...

it is:
AD^2 = \frac{2c^2 +2b^2 -a^2}{4}

ha ji aap correct ho.............

106

Asish Mahapatra ·2009-03-04 05:59:05

haan yahii hai.. Xth mein derive kiya tha bahut gande process se..

hehehe gud

haan 10th me thaa...

bad derivation :'(

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω