F(x) =√2 [(1/√2)sin x + (1/√2)cos x]=√2cos(45°-x)
max value of cos(45°-x) is +1
hence F(X)max=√2
F(x) = sin x + cos x, the maximum value of F(x) is
(a) 1
(b)√ 2
(c) √3
(d) 2
F(x) =√2 [(1/√2)sin x + (1/√2)cos x]=√2cos(45°-x)
max value of cos(45°-x) is +1
hence F(X)max=√2
THE ANSWER TTO THIS QUESTION IS √2
ITS SIMPLE
PUT X=PI/4 OR
THE STANDARD MAXIMUM VALUE OF
-√a2+b2≤asin x +bcos x ≤√a2+b2
remember this [1]
Max value of expression of form a sin x+b cos x is√a2+b2
So, max value is √2