229tan10tan70
=(2sin10sin70)/(2cos10cos70)
=(cos60-cos80)/(cos60+cos80)
=((1/2)-cos80)/((1/2)+cos80)
=(1-2cos 80)/(1+2cos 80)
therefore multiply tan30 with the expression above
and then i hope u'll be able to solve because i can't :-P
3 Answers
229
1708\hspace{-16}$May be the question is....\\\\\\ Calculate value of $\bf{\tan(10^0).\tan(30^0).\tan(50^0).\tan(70^0)=}$
- Dwijaraj Paul Chowdhury Then this can be solvedUpvote·0· Reply ·2013-02-24 05:32:22
