solve for least values x and y...
2(sin x + sin y) - 2 cos(x-y)=3.
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3 Answers
Hari Shankar
·2012-02-26 00:25:59
The equation can be rearranged as:
\left[2 \cos \left(\frac{x-y}{2} \right) - \sin \left(\frac{x+y}{2} \right)\right]^2+\cos^2 \left(\frac{x+y}{2} \right)=0