Is k1=2k2 the ans?
IF K1 = tan 27θ - tan θ and K2 = sin θcos 3θ + sin 3θcos 9θ + sin 9θcos 27θ, then
1. K1 = 2K2
2. K1 = K2 + 4
3. K1 = K2
4. none of these
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IF K1 = tan 27θ - tan θ and K2 = sin θcos 3θ + sin 3θcos 9θ + sin 9θcos 27θ, then
1. K1 = 2K2
2. K1 = K2 + 4
3. K1 = K2
4. none of these