Inverse Circular function:)

Solve
tan^-1+ 2cot^-1x=2Ï€/3

2 Answers

This one is really simple if you recall that tan^-1x+cot^-1x=Ï€/2

So effectively your question is asking for the solution of cot^-1x=2Ï€/3-Ï€/2 = Ï€/6

tan^-1x +2cot^-1x=2n3

We know that tan^-1x +cot^-1x =pi2

Therefore,

pi2 +cot^-1x =2n3
=>cot^-1x =2n3 - pi2
=>x=cot(2n3 - pi2)

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