Apply,
tain-1x + tan-1y = tan-1 (x+y)1-xy in tan-1(CotA) + tan-1(Cot3A) as
(1 + cot2A) will get cancelled from num. and denom. in the formula..
and break (1/2)(tan2A) which equals tanA1 - tan2A
and continue..!!
What is the value of tan-1((1/2)tan2A)+ tan-1(cotA)+ tan-1(cot3A) ?
Apply,
tain-1x + tan-1y = tan-1 (x+y)1-xy in tan-1(CotA) + tan-1(Cot3A) as
(1 + cot2A) will get cancelled from num. and denom. in the formula..
and break (1/2)(tan2A) which equals tanA1 - tan2A
and continue..!!