oh sorry it's sin-1x+tan-1x=pi/2
the answers given are
q2: c ,
q4:√3/3
- Himanshu Giria oh yes the answer for 2 is c because rhs is always positive so the lhs also needs to be positive
- Raunaq Saha thanks
1)If sin-1x + tan -1x = , then 2x2 + 1=
2)2 sin -1x = cos-1 (1 -2x2) is true for
a. -1<=x<=1
b.-1<=x<=0
c.0<=x<=1
d.None of these
3)7)If sin-1x+sin-1y=2pi/3, cos-1x–cos-1y=pi/3, the number of ordered pairs (x, y) is
a.0
b.1
c.2
d.None of these
4)tan(cos-1x) = sin(cot-11/2), x is ?
2 _ A
oh sorry it's sin-1x+tan-1x=pi/2
the answers given are
q2: c ,
q4:√3/3