11if k>1/2 so it could be any number
the the max value could be infinite when k->∞
so please re check ur ques
what is the max value of cosA + cosB + kcosC \left( 1/2<k<1 \right)in a triangle
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13 Answers
11112cos(A+B/2)cos(A-B)/2+kcosC
this will be maximum when A and are both 60° each
so u get √3+kcosC
AS IT IS A TRIANGLE SO A+B+C=∩
hence C=60°
answer must be √3+k√3/2
3draw graph and see ...... its interestin... already been done bfore i think...
11hmmmmmmmmmmmnnnnnnnnnnn
1st point equality is not given in the question
2nd why arent we getting the same answers[7]
if u find a flaw in my solution do post it!!!!!!!!![1]
3so maximum value is 3/2 .....dont understand y u posted ur first """point""
21FRIENDS : ITS SOLVD HERE
http://www.goiit.com/posts/list/algebra-if-a-b-c-pi-then-maximum-value-of-cosa-cosb-kcosc-where-912480.htm