Need a quick soln.

sin 2θ=14

64(sinθ+cosθ) -8(1cosθ+1sinθ) +sin²Î¸+cos²Î¸sinθcosθ

=64(sinθ+cosθ) -8sinθ+cosθsinθcosθ+1sinθcosθ

Multiplying and dividing by 2 in the second and the third fraction

=64(sinθ+cosθ) -16sinθ+cosθ2sinθcosθ+22sinθcosθ

=64(sinθ+cosθ) -16sinθ+cosθsin2θ+2sin2θ

sin 2θ=1/4

=64(sinθ+cosθ) -64(sinθ+cosθ)+8
=8 (Ans)