plzz solve this...

If A=320° then 2sin(A/2) = ?

a)√1+sinA -√1-sinA

B) √1+sinA +√1-sinA

C)-√1+sinA -√1-sinA

d)√1+sinA+√1-sinA

1 Answers

62
Lokesh Verma ·

√1+sinA = |sinA/2+cosA/2|
√1-sinA = |sinA/2-cosA/2|

this is hint enuf? Actually this is the complete solution (almost) :)

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