If A=320° then 2sin(A/2) = ?
a)√1+sinA -√1-sinA
B) √1+sinA +√1-sinA
C)-√1+sinA -√1-sinA
d)√1+sinA+√1-sinA
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1 Answers
Lokesh Verma
·2008-11-16 07:37:18
√1+sinA = |sinA/2+cosA/2|
√1-sinA = |sinA/2-cosA/2|
this is hint enuf? Actually this is the complete solution (almost) :)