1well see that
sinC=csinB/b
now if one value satisfying is C then the other is π-C
so we get A1=Ï€-(B+C)
A2=Ï€-(B+Ï€-C)=C-B
A1-A2=Ï€-B-C-C+B=Ï€-2C
A1-A2/2 = π/2-C
so we have cos(A1-A2/2)=sinC=csinB/b
had bunked POT last yr becuz it was very booring ...... now i face the heat ...
if b c and B are given and let c > b .......
if A1,A2 be 2 possible values of A .........
find the value of cos[(A1 - A2)/2] ........................
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10 Answers
1b/sin B = c/ sin C
get the value of C
u'll get 2 values of C
u know B & C
u'll get A .. since C takes 2 values .. A takes 2 values ...
then find ... i got this .. i think there must be an easier approach !
1
9you seem to be bunking half of jee portions
change ur attitude if u want an excellent rank in jee
3rohan didnt get u .......... cud u pls explain in detail!!!!!!!!
now if one value satisfying is C then the other is π-C
why???
i may sound stupid .. but im only a beginner pls help///
39nothing stupid in this . well u just could not get the point. shraman , well leaving out such tpics would mean just leaving out some easily gettable marks in jee.