prove...

tan 8θ - tan 6θ - tan 2θ =tan8θtan6θtan2θ

1 Answers

996
Swarna Kamal Dhyawala ·

tan 8A = tan (6A +2A)
= tan6A + tan2A / 1- tan6A tan2A
crossmultiplying
tan8A - tan8A tan6A tan2A = tan6A + tan2A
tan8A - tan6A - tan2A = tan8A tan6A tan2A
Proved.......

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